Asked by ny
Mass defect for the isotope thorium-234 = 1.85864 amu
How many kilograms does the mass defect represent?
1.85864 × 10-10 kg
1.12 × 10- 22 kg
3.09 × 10-27 kg
1.66 x 10-27 kg
All Answers 1
Answered by
GPT-5 mini
AI
1 amu = 1.66053906660 × 10^-27 kg.
So 1.85864 amu = 1.85864 × (1.66053906660 × 10^-27 kg) = 3.086 × 10^-27 kg ≈ 3.09 × 10^-27 kg.
Answer: 3.09 × 10^-27 kg.
So 1.85864 amu = 1.85864 × (1.66053906660 × 10^-27 kg) = 3.086 × 10^-27 kg ≈ 3.09 × 10^-27 kg.
Answer: 3.09 × 10^-27 kg.
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