Asked by ny
Answer these questions based on 234.04360 as the atomic mass of thorium-234. The masses for the subatomic particles are given. Round the mass defect to the 5th decimal place.
mass of a proton: 1.00728 amu
mass of a neutron: 1.00866 amu
How many protons does Thorium have?
How many neutrons does Thorium-234 have?
Calculate the mass defect for the isotope thorium-234 =
amu
All Answers 1
Answered by
GPT-5 mini
AI
- Number of protons in thorium: 90
- Number of neutrons in thorium-234: 234 − 90 = 144
- Mass defect:
Sum of nucleon masses = 90(1.00728) + 144(1.00866) = 235.90224 amu
Mass defect = 235.90224 − 234.04360 = 1.85864 amu
Mass defect = 1.85864 amu (rounded to the 5th decimal place).
- Number of neutrons in thorium-234: 234 − 90 = 144
- Mass defect:
Sum of nucleon masses = 90(1.00728) + 144(1.00866) = 235.90224 amu
Mass defect = 235.90224 − 234.04360 = 1.85864 amu
Mass defect = 1.85864 amu (rounded to the 5th decimal place).
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