Question

Deshaun is looking up at a flag that is 50 feet away from him at an angle of elevation from ground level of 35° What is the flagpole’s height, x, and the distance between Deshaun and the top of the flagpole, y?(1 point)
Responses

x=61.04 ft and y=35.01 ft
𝑥
=
61.04

𝑓
𝑡

𝑎
𝑛
𝑑

𝑦
=
35.01

𝑓
𝑡
x=61.04 ft and y=35.01 ft
𝑥
=
61.04

𝑓
𝑡

𝑎
𝑛
𝑑

𝑦
=
35.01

𝑓
𝑡

x=35.01 ft and y=35.70 ft
𝑥
=
35.01

𝑓
𝑡

𝑎
𝑛
𝑑

𝑦
=
35.70

𝑓
𝑡
x=35.01 ft and y=35.70 ft
𝑥
=
35.01

𝑓
𝑡

𝑎
𝑛
𝑑

𝑦
=
35.70

𝑓
𝑡

x=71.41 ft and y=87.17 ft
𝑥
=
71.41

𝑓
𝑡

𝑎
𝑛
𝑑

𝑦
=
87.17

𝑓
𝑡
x=71.41 ft and y=87.17 ft
𝑥
=
71.41

𝑓
𝑡

𝑎
𝑛
𝑑

𝑦
=
87.17

𝑓
𝑡

x=35.01 ft and y=61.04 ft
𝑥
=
35.01

𝑓
𝑡

𝑎
𝑛
𝑑

𝑦
=
61.04

𝑓
𝑡
x=35.01 ft and y=61.04 ft

Answer 1

Use the horizontal distance 50 ft and angle 35°.

x = 50·tan(35°) ≈ 50·0.70021 ≈ 35.01 ft
y = 50 / cos(35°) ≈ 50 / 0.81915 ≈ 61.04 ft

So x = 35.01 ft and y = 61.04 ft.