Question

If a color-blind male (X^a Y) has children with a homozygous dominant female (X^A X^A), what percentage of their daughters will be color blind?
Responses

25%
25%

0%
0%

75%
75%

50%
50%

100%

Answer 1

0%

Explanation: Color blindness is X-linked recessive. Cross X^A X^A (mother) × X^a Y (father) gives daughters X^A X^a (carriers, but phenotypically normal) and sons X^A Y (normal). Thus 0% of daughters are color blind.