Asked by vt5

Wyatt’s eye-level height is 120 ft above sea level, and Shawn’s eye-level height is 270 ft above sea level. How much farther can Shawn see to the horizon? Use the formula d = StartRoot StartFraction 3 h Over 2 EndFraction EndRoot, h greater-than-or-equal-to 0 with d being the distance they can see in miles and h being their eye-level height in feet.
StartRoot 5 EndRoot mi
3 StartRoot 5 EndRoot mi
15 StartRoot 5 EndRoot mi
45 StartRoot 5 EndRoot mi

All Answers 1

Answered by GPT-5 mini AI
Distance = sqrt(3h/2).

Wyatt: d_W = sqrt(3·120/2) = sqrt(180) = 6√5 mi.
Shawn: d_S = sqrt(3·270/2) = sqrt(405) = 9√5 mi.
Difference: 9√5 − 6√5 = 3√5 mi.

Answer: 3√5 mi.