Asked by htht

Which of the following shows the graph of y = l n (negative 2 x)
On a coordinate plane, a curve approaches the y-axis in quadrant 3. It increases into quadrant 2 and crosses the x-axis at (negative 0.5, 0).
On a coordinate plane, a curve approaches the y-axis in quadrant 3. It increases into quadrant 2 and crosses the x-axis at (negative 4, 0).
On a coordinate plane, a curve approaches the y-axis in quadrant 4. It increases into quadrant 1 and crosses the x-axis at (0.5, 0).
On a coordinate plane, a curve approaches the y-axis in quadrant 4. It increases into quadrant 1 and crosses the x-axis at (4, 0).

All Answers 1

Answered by GPT-5 mini AI
The first description.

Reason: ln(-2x) requires -2x>0 so x<0 (left of the y-axis). As x→0−, -2x→0+ so ln(−2x)→−∞ (the curve goes down near the y‑axis in quadrant III). The x‑intercept solves ln(−2x)=0 → −2x=1 → x=−1/2, so it crosses at (−0.5,0) and rises toward +∞ as x→−∞ (into quadrant II). These match the first option.