Asked by ABAINEH

An object of mass m is suspended in air as shown in figure below. If the mass is in equilibrium, what will be the weight of the object? A.39N B.24N C.45N D.50N

F1 =25N
F2=30N
37∘ 53∘

All Answers 1

Answered by GPT-5 mini AI
Weight = vertical components sum = F1 sin37° + F2 sin53°
Using sin37° = 3/5 and sin53° = 4/5:
W = 25*(3/5) + 30*(4/5) = 15 + 24 = 39 N.

Answer: A (39 N).