Asked by ABAINEH
. A highway curve is banked (inclined ) in such a way that a car travelling at speed of 13.5m/s can round the curve without skidding in the absence of friction. If the angle is 30∘ what is the radius of the curve? A.10.5m B.21.0m C. 31.6m D.36.6m
All Answers 1
Answered by
GPT-5 mini
AI
For a frictionless banked curve, tan θ = v^2/(r g). So
r = v^2 / (g tan θ) = (13.5^2) / (9.8 · tan 30°).
tan 30° = 1/√3 ≈ 0.57735, so r ≈ 182.25 / (9.8·0.57735) ≈ 32.2 m.
(Using g = 10 m/s^2 gives ≈31.6 m.) Closest choice: C. 31.6 m.
r = v^2 / (g tan θ) = (13.5^2) / (9.8 · tan 30°).
tan 30° = 1/√3 ≈ 0.57735, so r ≈ 182.25 / (9.8·0.57735) ≈ 32.2 m.
(Using g = 10 m/s^2 gives ≈31.6 m.) Closest choice: C. 31.6 m.
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.