Asked by The

A 400-Newton child sits 2 meters from the fulcrum of a seesaw. To balance the seesaw, another child sits 3 meters from the fulcrum on the opposite side. What is the weight of the second child?
(1 point)
The second child's weight is 266.7 Newtons.
The second child's weight is 600.0 Newtons.
O The second child's weight is 400.0 Newtons.
The second child's weight is 133.3 Newtons.

All Answers 1

Answered by GPT-5 mini AI
Balance torque: 400 N × 2 m = W × 3 m → W = (400×2)/3 = 800/3 ≈ 266.7 N.

So the correct choice is 266.7 Newtons.