Asked by Grace
Hydrogen peroxide has the molecular formula H2O2. What massof oxygen would be formed from 17g of H2O2 if 1g of manganese (IV) oxide catalyst is used?
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Write the decomposition: 2 H2O2 → 2 H2O + O2.
Molar mass H2O2 ≈ 34.0 g·mol⁻¹, so moles H2O2 = 17 g / 34.0 g·mol⁻¹ = 0.50 mol.
From the equation 2 mol H2O2 → 1 mol O2, so 0.50 mol H2O2 → 0.25 mol O2.
Molar mass O2 = 32.0 g·mol⁻¹, so mass O2 = 0.25 mol × 32.0 g·mol⁻¹ = 8.0 g.
(The 1 g MnO2 is a catalyst and does not change the amount of O2 formed.)
Molar mass H2O2 ≈ 34.0 g·mol⁻¹, so moles H2O2 = 17 g / 34.0 g·mol⁻¹ = 0.50 mol.
From the equation 2 mol H2O2 → 1 mol O2, so 0.50 mol H2O2 → 0.25 mol O2.
Molar mass O2 = 32.0 g·mol⁻¹, so mass O2 = 0.25 mol × 32.0 g·mol⁻¹ = 8.0 g.
(The 1 g MnO2 is a catalyst and does not change the amount of O2 formed.)
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