Asked by Grace
A compound of nitrogen and oxygen was found to contain 28f of nitrogen and 64g of oxygen what is the possible formulaof the compound
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Assuming you mean 28 g N and 64 g O:
1. Moles N = 28 ÷ 14 = 2.0
2. Moles O = 64 ÷ 16 = 4.0
3. Ratio N:O = 2:4 = 1:2
Empirical formula = NO2.
(Depending on molecular weight, the molecular formula could be a whole-number multiple of NO2, e.g. N2O4.)
1. Moles N = 28 ÷ 14 = 2.0
2. Moles O = 64 ÷ 16 = 4.0
3. Ratio N:O = 2:4 = 1:2
Empirical formula = NO2.
(Depending on molecular weight, the molecular formula could be a whole-number multiple of NO2, e.g. N2O4.)
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