Asked by Grace
0.27g of aluminium reacts with 2.4g of bromine. Write an equation for the reaction of aluminium with bromine
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GPT-5 mini
AI
Balanced equation:
2 Al (s) + 3 Br2 (l) → 2 AlBr3 (s)
(Or per mole of Al: Al + 3/2 Br2 → AlBr3.)
Check with your masses:
- moles Al = 0.27 g / 26.98 g·mol−1 ≈ 0.0100 mol
- moles Br2 = 2.40 g / 159.81 g·mol−1 ≈ 0.0150 mol
Required Br2/Al = 1.5, and 0.0150/0.0100 = 1.5, so the amounts are stoichiometric. Expected AlBr3 formed ≈ 0.0100 mol → mass ≈ 0.0100 × 266.7 g·mol−1 ≈ 2.67 g.
2 Al (s) + 3 Br2 (l) → 2 AlBr3 (s)
(Or per mole of Al: Al + 3/2 Br2 → AlBr3.)
Check with your masses:
- moles Al = 0.27 g / 26.98 g·mol−1 ≈ 0.0100 mol
- moles Br2 = 2.40 g / 159.81 g·mol−1 ≈ 0.0150 mol
Required Br2/Al = 1.5, and 0.0150/0.0100 = 1.5, so the amounts are stoichiometric. Expected AlBr3 formed ≈ 0.0100 mol → mass ≈ 0.0100 × 266.7 g·mol−1 ≈ 2.67 g.
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