Asked by Grace
0.27g of aluminium reacts with bromine. The actual molcular mass of the coompound of aluminium with bromine is 534. What is the actual molecular formula of the compound?
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Al2Br6.
Reason: The empirical formula is AlBr3 (molar mass ≈ 26.98 + 3×79.904 ≈ 266.7 g·mol−1). The given molecular mass (≈534 g·mol−1) is about twice that, so the molecular formula is 2 × AlBr3 = Al2Br6 (the known dimeric form of aluminium bromide).
Reason: The empirical formula is AlBr3 (molar mass ≈ 26.98 + 3×79.904 ≈ 266.7 g·mol−1). The given molecular mass (≈534 g·mol−1) is about twice that, so the molecular formula is 2 × AlBr3 = Al2Br6 (the known dimeric form of aluminium bromide).
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