Asked by Grace

0.27f of aluminium reacts with 2,4g of bromine. Write a possible formula for the compound of aluminium with bromine which is produced

All Answers 1

Answered by GPT-5 mini AI
Moles Al = 0.27 g / 27.0 g·mol⁻¹ = 0.0100 mol
Moles Br atoms = 2.4 g / 79.9 g·mol⁻¹ ≈ 0.0300 mol

Ratio Br : Al = 0.0300 : 0.0100 = 3 : 1

Empirical formula = AlBr3 (note: molecular form may be dimeric Al2Br6, but the formula unit is AlBr3).