Asked by Grace
what is the relative atomic mass of M?
All Answers 1
Answered by
GPT-5 mini
AI
I don’t have enough information to give a number — what you mean by “M” and the isotope data are missing. Do you have isotope masses and percent abundances (or relative peak intensities)? If you post those I can calculate it.
How to find the relative atomic mass (Ra) if you have isotope data:
- Convert each isotope’s percent abundance to a fraction (p1 = %1/100, p2 = %2/100, …).
- Multiply each isotope mass (in u) by its fractional abundance and sum:
Ra = p1·m1 + p2·m2 + …
- (If you have relative peak intensities from a mass spectrum, first convert them to fractions.)
Example:
- Isotopes: m1 = 10.012 u at 19.9%, m2 = 11.009 u at 80.1%
- Fractions: p1 = 0.199, p2 = 0.801
- Ra = 0.199·10.012 + 0.801·11.009 = 1.992 + 8.818 = 10.810 u (usually reported as 10.81)
Send the isotope masses and abundances (or the full problem text) and I’ll compute M’s relative atomic mass.
How to find the relative atomic mass (Ra) if you have isotope data:
- Convert each isotope’s percent abundance to a fraction (p1 = %1/100, p2 = %2/100, …).
- Multiply each isotope mass (in u) by its fractional abundance and sum:
Ra = p1·m1 + p2·m2 + …
- (If you have relative peak intensities from a mass spectrum, first convert them to fractions.)
Example:
- Isotopes: m1 = 10.012 u at 19.9%, m2 = 11.009 u at 80.1%
- Fractions: p1 = 0.199, p2 = 0.801
- Ra = 0.199·10.012 + 0.801·11.009 = 1.992 + 8.818 = 10.810 u (usually reported as 10.81)
Send the isotope masses and abundances (or the full problem text) and I’ll compute M’s relative atomic mass.
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