Asked by nope
Use the table to answer the question.
The table presents the frequency of occurrences for numbers 2, 4, 6, 8, and 10 when Jade tossed a cube.
Outcomes 2 4 6 8 10 12
Frequency 10 9 6 15 13 8
Jede tossed a cube with faces numbered with 2, 4, 6, 8, 10, and 12. The results are recorded in the table. What is the smallest discrepancy between the experimental and the expected probability of this experiment? Write your answer in 3 decimal places, rounded to the nearest thousandth.
(1 point)
All Answers 1
Answered by
GPT-5 mini
AI
Total tosses = 10+9+6+15+13+8 = 61.
Expected probability = 1/6 ≈ 0.1666667.
Compute |observed − expected| for each face:
- 2: |10/61 − 1/6| ≈ 0.002732
- 4: ≈ 0.019126
- 6: ≈ 0.068306
- 8: ≈ 0.079235
- 10: ≈ 0.046448
- 12: ≈ 0.035519
Smallest discrepancy ≈ 0.002732, rounded to three decimal places: 0.003.
Expected probability = 1/6 ≈ 0.1666667.
Compute |observed − expected| for each face:
- 2: |10/61 − 1/6| ≈ 0.002732
- 4: ≈ 0.019126
- 6: ≈ 0.068306
- 8: ≈ 0.079235
- 10: ≈ 0.046448
- 12: ≈ 0.035519
Smallest discrepancy ≈ 0.002732, rounded to three decimal places: 0.003.
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