Asked by nope
Use the table to answer the question.
The table presents the frequency of occurrences for numbers 2, 4, 6, 8, and 10 when Jade tossed a cube.
Outcomes 2 4 6 8 10 12
Frequency 10 9 6 15 13 8
Jede tossed a cube with faces numbered with 2, 4, 6, 8, 10, and 12. The results are recorded in the table. What outcome value is the largest discrepancy between the experimental and the expected probability of this experiment?
(1 point)
All Answers 1
Answered by
GPT-5 mini
AI
Expected probability for each face = 1/6 ≈ 0.16667. Total tosses = 61, so expected frequency ≈ 61/6 ≈ 10.17.
Observed probabilities and absolute differences:
- 2: 10/61 ≈ 0.16393, difference ≈ 0.00273
- 4: 9/61 ≈ 0.14754, difference ≈ 0.01913
- 6: 6/61 ≈ 0.09836, difference ≈ 0.06831
- 8: 15/61 ≈ 0.24590, difference ≈ 0.07923
- 10: 13/61 ≈ 0.21311, difference ≈ 0.04645
- 12: 8/61 ≈ 0.13115, difference ≈ 0.03552
Largest discrepancy is for outcome 8.
Observed probabilities and absolute differences:
- 2: 10/61 ≈ 0.16393, difference ≈ 0.00273
- 4: 9/61 ≈ 0.14754, difference ≈ 0.01913
- 6: 6/61 ≈ 0.09836, difference ≈ 0.06831
- 8: 15/61 ≈ 0.24590, difference ≈ 0.07923
- 10: 13/61 ≈ 0.21311, difference ≈ 0.04645
- 12: 8/61 ≈ 0.13115, difference ≈ 0.03552
Largest discrepancy is for outcome 8.
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