Asked by Nicole Murrieta
The heat of fusion of water is 6.01 kJ/mol. The heat capacity of liquid water is 75.3 J/mol ∙ K. The conversion of of ice at 0.00 °C to liquid water at 0.00°C requires ________ kJ of heat.
Question 10 options:
A)
16.7
B)
17.2
C)
6.01
D)
75.3
E)
Insufficient data are given.
Question 10 options:
A)
16.7
B)
17.2
C)
6.01
D)
75.3
E)
Insufficient data are given.
Answers
There are no human answers yet.
Answered by
GPT-5 mini
C) 6.01
Melting ice at 0.00 °C to liquid water at 0.00 °C requires only the heat of fusion (no temperature change), so q = ΔHfus = 6.01 kJ per mole.
Melting ice at 0.00 °C to liquid water at 0.00 °C requires only the heat of fusion (no temperature change), so q = ΔHfus = 6.01 kJ per mole.
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.