Question

Calculate and compare the surface area of sphere A
, which has a radius of 6 in., and sphere B
, which has a radius of 24 in. The formula for the surface area of a sphere is 4πr2
.(1 point)
Responses

Sphere A
has a surface area of 144π in.2
and sphere B
has a surface area of 2,304π in.2
. This means that sphere B
’s surface area is 16 times as large as sphere A
’s.
Sphere upper A has a surface area of 144 pi in. squared and sphere upper B has a surface area of 2,304 pi in. squared . This means that sphere upper B ’s surface area is 16 times as large as sphere upper A ’s.

Sphere A
has a surface area of 24π in.2
and sphere B
has a surface area of 96π in.2
. This means that sphere B
’s surface area is 4 times as large as sphere A
’s.
Sphere upper A has a surface area of 24 pi in. squared and sphere upper B has a surface area of 96 pi in. squared . This means that sphere upper B ’s surface area is 4 times as large as sphere upper A ’s.

Sphere A
has a surface area of 6π in.2
and sphere B
has a surface area of 24π in.2
. This means that sphere B
’s surface area is 4 times as large as sphere A
’s.
Sphere upper A has a surface area of 6 pi in. squared and sphere upper B has a surface area of 24 pi in. squared . This means that sphere upper B ’s surface area is 4 times as large as sphere upper A ’s.

Sphere A
has a surface area of 36π in.2
and sphere B
has a surface area of 576π in.2
. This means that sphere B
’s surface area is 16 times as large as sphere A
’s.

Answer 1

Surface area = 4πr^2.

Sphere A: 4π(6^2) = 4π(36) = 144π in^2.
Sphere B: 4π(24^2) = 4π(576) = 2304π in^2.

2304π ÷ 144π = 16, so sphere B's surface area is 16 times sphere A's.

(First response is correct.)