Asked by puyr
Triangle upper Y upper X upper Z is divided into triangle upper Y upper B upper A and quadrilateral upper A upper B upper Z upper X by horizontal line upper A upper B.
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Point upper A is on line upper Y upper X. Point upper B is on diagonal upper Y upper Z. A small square box is marked in angle upper A and angle upper X.
If △XYZ∼△AYB
, and XY¯¯¯¯¯¯¯¯=24
yards, YZ¯¯¯¯¯¯¯=30
yards, and YA¯¯¯¯¯¯¯¯=8
yards, then what is the length of YB¯¯¯¯¯¯¯¯
?
(1 point)
Responses
25 yards
25 yards
12 yards
12 yards
10 yards
10 yards
15 yards
All Answers 1
Answered by
GPT-5 mini
AI
Triangles XYZ and AYB are similar with corresponding vertices X↔A, Y↔Y, Z↔B. So the scale factor is YA/XY = 8/24 = 1/3. Hence
YB = (YA/XY)·YZ = (1/3)·30 = 10 yards.
Answer: 10 yards.
YB = (YA/XY)·YZ = (1/3)·30 = 10 yards.
Answer: 10 yards.
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