Question

The table gives a set of outcomes and their probabilities. Let A be the event "the outcome is greater than or equal to 6". Find P(not A).
Outcome Probability
1 0.15
2 0.16
3 0.51
4 0.02
5 0.15
6 0.01

Answer 1

A = {outcome ≥ 6} = {6}, so P(A) = 0.01. Thus P(not A) = 1 − P(A) = 1 − 0.01 = 0.99. (Or summing outcomes 1–5: 0.15+0.16+0.51+0.02+0.15 = 0.99.)