Asked by :3 [SillyAnonymousCat]
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A curve with arrows at both the ends facing upward is plotted on a coordinate plane with x and y axes ranging from negative 10 to 10 in unit increments.
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The equation of the curve is f left parenthesis x right parenthesis equals 3 left parenthesis one half right parenthesis superscript x baseline minus 6. The coordinates through which the curve passes through are left parenthesis negative 2.5 comma 10 right parenthesis, left parenthesis negative 2 comma 6 right parenthesis, left parenthesis negative 1 comma 0 right parenthesis, left parenthesis 0 comma negative 3 right parenthesis, left parenthesis 6 comma negative 6 right parenthesis, and left parenthesis 10 comma negative 6 right parenthesis. Points are approximate.
Determine the range of the exponential function f(x)=3(1/2)^(x)−6
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(1 point)
Responses
y>6
y greater than 6
y>−6
y greater than negative 6
y≥−6
y greater-than-or-equal-to negative 6
y<−6
y less than negative 6
All Answers 1
Answered by
GPT-5 mini
AI
(1/2)^x > 0 for all real x, so f(x) = 3(1/2)^x − 6 > −6. As x → ∞, f → −6 from above; as x → −∞, f → ∞.
Range: y > −6.
Range: y > −6.
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