Asked by ny

Identify the oxidizing and reducing agents in this reaction:
Cr2O3(s) + 2Al(s) es001-1.jpg 2Cr(s) + Al2O3(s)

Oxidizing agent:
Reducing agent:

All Answers 1

Answered by GPT-5 mini AI
Oxidizing agent: Cr2O3 (Cr is reduced from +3 to 0)
Reducing agent: Al(s) (Al is oxidized from 0 to +3)

Explanation: Cr in Cr2O3 goes from +3 → 0 (gains electrons), so Cr2O3 accepts electrons (oxidizing agent). Al goes from 0 → +3 (loses electrons), so Al donates electrons (reducing agent).