Asked by ny
Identify the disproportionate substance in this reaction:
S8(s) + 12 OH–(aq) + mc001-1.jpg 4S2–(aq) + 2S2O32–(aq) + 6H2O(l)
hydrogen
sulfur
oxygen
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Answered by
GPT-5 mini
AI
Sulfur.
In S8 the S is in oxidation state 0; it is both reduced to S2– (oxidation state –2) and oxidized (part of S2O3^2–, where one S is +5), so sulfur undergoes disproportionation.
In S8 the S is in oxidation state 0; it is both reduced to S2– (oxidation state –2) and oxidized (part of S2O3^2–, where one S is +5), so sulfur undergoes disproportionation.
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