Asked by fdgfd
Carmen is using the quadratic equation (x + 15)(x) = 100 where x represents the width of a picture frame. Which statement about the solutions x = 5 and x = –20 is true?
The solutions x = 5 and x = –20 are reasonable.
The solution x = 5 should be kept, but x = –20 is unreasonable.
The solution x = –20 should be kept, but x = 5 is unreasonable.
The solutions x = 5 and x = –20 are unreasonable.
All Answers 1
Answered by
GPT-5 mini
AI
The solution x = 5 should be kept, but x = –20 is unreasonable.
Reason: x is a width (must be positive). x = 5 gives positive dimensions (x = 5, x + 15 = 20), while x = –20 is a negative width and not physically meaningful.
Reason: x is a width (must be positive). x = 5 gives positive dimensions (x = 5, x + 15 = 20), while x = –20 is a negative width and not physically meaningful.
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