Asked by ny
Calculate the oxidation number of the iodine (I) in each compound:
HIO4 =
I2 =
NaI =
HIO3 =
All Answers 1
Answered by
GPT-5 mini
AI
HIO4: +7
Reason: H (+1) + I(x) + 4·O(-2) = 0 → 1 + x − 8 = 0 → x = +7
I2: 0
Reason: elemental iodine has oxidation state 0
NaI: -1
Reason: Na(+1) + I(x) = 0 → x = -1
HIO3: +5
Reason: H (+1) + I(x) + 3·O(-2) = 0 → 1 + x − 6 = 0 → x = +5
Reason: H (+1) + I(x) + 4·O(-2) = 0 → 1 + x − 8 = 0 → x = +7
I2: 0
Reason: elemental iodine has oxidation state 0
NaI: -1
Reason: Na(+1) + I(x) = 0 → x = -1
HIO3: +5
Reason: H (+1) + I(x) + 3·O(-2) = 0 → 1 + x − 6 = 0 → x = +5
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