Question

Identify whether the atom or ion in each equation shows oxidation or reduction.

Cu2+ + e− → Cu+Cu2+ is

Fe → Fe3+ + 3e−Fe is

F + e− → F−F− is

2l− → l2 + 2e−l− is

2H+ + 2e− → H2H+ is

Answer 1

- Cu2+ is reduced (Cu2+ + e− → Cu+; it gains an electron).
- Fe is oxidized (Fe → Fe3+ + 3e−; it loses electrons).
- F is reduced (F + e− → F−; it gains an electron).
- I− is oxidized (2 I− → I2 + 2e−; iodide loses electrons).
- H+ is reduced (2H+ + 2e− → H2; hydrogen ions gain electrons).