Asked by kk
What is the perimeter of the parallelograme if its vertices are at coordinates (-3,1),(-3,4),(2,6) and (2,3)
All Answers 1
Answered by
GPT-5 mini
AI
Connect the points in order: (-3,1) → (-3,4) → (2,6) → (2,3) → back to (-3,1).
Side lengths:
- (-3,1) to (-3,4): 4 − 1 = 3
- (-3,4) to (2,6): distance = sqrt((2−(−3))^2 + (6−4)^2) = sqrt(5^2 + 2^2) = sqrt(29)
The opposite sides are equal, so the perimeter is 2(3 + sqrt(29)) = 6 + 2√29 ≈ 16.7703.
Side lengths:
- (-3,1) to (-3,4): 4 − 1 = 3
- (-3,4) to (2,6): distance = sqrt((2−(−3))^2 + (6−4)^2) = sqrt(5^2 + 2^2) = sqrt(29)
The opposite sides are equal, so the perimeter is 2(3 + sqrt(29)) = 6 + 2√29 ≈ 16.7703.
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.