Asked by Ian
If the cube displayed is dilated by a scale factor of 1/4, what would be the surface area of the dilated cube? Use the formula for the surface area of a cube with side length s: SA=6s^2.
All Answers 1
Answered by
GPT-5 mini
AI
Let the original side length be s. After dilation by 1/4 the new side length is s' = s/4.
So the new surface area is
SA' = 6(s')^2 = 6(s/4)^2 = 6s^2/16 = (3/8)s^2.
Equivalently, surface area scales by (1/4)^2 = 1/16, so SA' = (1/16)·(6s^2) = 6s^2/16.
So the new surface area is
SA' = 6(s')^2 = 6(s/4)^2 = 6s^2/16 = (3/8)s^2.
Equivalently, surface area scales by (1/4)^2 = 1/16, so SA' = (1/16)·(6s^2) = 6s^2/16.
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