Asked by george
I am so bad when it comes to mathI I think I am slow! okay so my question is :
a recrusive sequence is defined by tn= 2tn-1, where t1= 5
define the first five terms of this sequnce:
so would I go like this to figure them out:
2tn-1, where t1= 5
so
2(5)(1-1)= 0
so the frist 5 are: 0, 10, 20, 30,40
am I correct or am I doing it horribley wrong?
okay there is a part b!
it says would the points of the sequence, (n,Tn), lie on the graph of an exponentail function, linear function or neithr?
I would have to say neither
am I wrong?
You have t<sub>n</sub> = 2t<sub>n-1</sub> - 1, where t<sub>1</sub>= 5
I think your second term is wrong.
t<sub>2</sub> = 2t<sub>1</sub> - 1 =2*5-1 = 9
t<sub>3</sub> = 2t<sub>2</sub> - 1 =2*9-1 = 17
t<sub>4</sub> = 2t<sub>3</sub> - 1 =2*17-1 = 33
You're not "horribly" wrong, but you probably just need to see how to get started.
The fist few points look like
n T<sub>n</sub>
1
a recrusive sequence is defined by tn= 2tn-1, where t1= 5
define the first five terms of this sequnce:
so would I go like this to figure them out:
2tn-1, where t1= 5
so
2(5)(1-1)= 0
so the frist 5 are: 0, 10, 20, 30,40
am I correct or am I doing it horribley wrong?
okay there is a part b!
it says would the points of the sequence, (n,Tn), lie on the graph of an exponentail function, linear function or neithr?
I would have to say neither
am I wrong?
You have t<sub>n</sub> = 2t<sub>n-1</sub> - 1, where t<sub>1</sub>= 5
I think your second term is wrong.
t<sub>2</sub> = 2t<sub>1</sub> - 1 =2*5-1 = 9
t<sub>3</sub> = 2t<sub>2</sub> - 1 =2*9-1 = 17
t<sub>4</sub> = 2t<sub>3</sub> - 1 =2*17-1 = 33
You're not "horribly" wrong, but you probably just need to see how to get started.
The fist few points look like
n T<sub>n</sub>
1
Answers
Answered by
Anonymouse
okay now can anyone hellp me too
Answered by
Anonymouse
i also need help
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