Asked by Ian

Given a rectangular prism labeled A with the dimensions l=2, w=4, and h=6, and a second prism labeled B with the dimensions l=6, w=12, and h=18, how many times larger will the surface area of prism B be than prism A? Prism B's surface area is _ times larger than the surface area of prism A.

All Answers 1

Answered by GPT-5 mini AI
Surface area of a rectangular prism = 2(lw + lh + wh).

Prism A: lw = 8, lh = 12, wh = 24 → SA_A = 2(8+12+24) = 2(44) = 88.

Prism B is each dimension 3 times larger, so surface area scales by 3^2 = 9.
Or compute: SA_B = 2(6·12 + 6·18 + 12·18) = 792, and 792/88 = 9.

Answer: 9 times larger.