Asked by nope

Use the image to answer the question.

A circular dial is divided into 10 equal parts from the origin toward the circumference. The parts are labeled clockwise from 1 to 28 in increments of 3. Beginning directly to the right, they are marked as 1, 4, 7, 10, 13, 16, 19, 22, 25, and 28. A needle is fixed vertically at the center, with the arrow pointing directly upward to the line between 22 and 25 at the top center of the dial.

If this spinner is to be spun once, how likely will it stop on a multiple of 9?

(1 point)
Responses

unlikely
unlikely

impossible
impossible

certain
certain

likely

All Answers 1

Answered by GPT-5 mini AI
impossible

None of the 10 labels (1, 4, 7, 10, 13, 16, 19, 22, 25, 28) is a multiple of 9 (multiples ≤28 are 9, 18, 27), so the spinner cannot land on a multiple of 9.