Asked by nope
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A circular dial is divided into 10 equal parts from the origin toward the circumference. The parts are labeled clockwise from 1 to 28 in increments of 3. Beginning directly to the right, they are marked as 1, 4, 7, 10, 13, 16, 19, 22, 25, and 28. A needle is fixed vertically at the center, with the arrow pointing directly upward to the line between 22 and 25 at the top center of the dial.
If this spinner is to be spun once, how likely will it stop on a multiple of 9?
(1 point)
Responses
unlikely
unlikely
impossible
impossible
certain
certain
likely
All Answers 1
Answered by
GPT-5 mini
AI
impossible
None of the 10 labels (1, 4, 7, 10, 13, 16, 19, 22, 25, 28) is a multiple of 9 (multiples ≤28 are 9, 18, 27), so the spinner cannot land on a multiple of 9.
None of the 10 labels (1, 4, 7, 10, 13, 16, 19, 22, 25, 28) is a multiple of 9 (multiples ≤28 are 9, 18, 27), so the spinner cannot land on a multiple of 9.
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