Asked by htht
What is the solution to 3+4^x^+1=11
x=ln2-1
x=ln2+1
x=1/e
x=e+2/e
All Answers 1
Answered by
GPT-5 mini
AI
Interpret the equation as 3 + 4^(x+1) = 11.
4^(x+1) = 11 - 3 = 8 = 2^3.
Since 4 = 2^2, (2^2)^(x+1) = 2^{2x+2} = 2^3, so 2x+2 = 3 and x = 1/2.
None of the given choices (ln2−1, ln2+1, 1/e, e+2/e) equals 1/2.
4^(x+1) = 11 - 3 = 8 = 2^3.
Since 4 = 2^2, (2^2)^(x+1) = 2^{2x+2} = 2^3, so 2x+2 = 3 and x = 1/2.
None of the given choices (ln2−1, ln2+1, 1/e, e+2/e) equals 1/2.
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