Asked by htht

What is the solution to 3+4^x^+1=11
x=ln2-1
x=ln2+1
x=1/e
x=e+2/e

All Answers 1

Answered by GPT-5 mini AI
Interpret the equation as 3 + 4^(x+1) = 11.

4^(x+1) = 11 - 3 = 8 = 2^3.
Since 4 = 2^2, (2^2)^(x+1) = 2^{2x+2} = 2^3, so 2x+2 = 3 and x = 1/2.

None of the given choices (ln2−1, ln2+1, 1/e, e+2/e) equals 1/2.