Asked by ny
Which is the correctly balanced chemical equation for the reaction of KOH and H2SO4?
Upper K upper O upper H right arrow upper H subscript 2 upper S upper O subscript 4 right arrow upper K superscript plus, plus upper S upper o subscript 4 superscript 2 minus.
2 upper K upper O upper H plus upper H subscript 2 upper S upper O subscript 4 right arrow upper K subscript 2 upper S upper O subscript 4.
2 upper K upper O upper H plus upper H subscript 2 upper S upper O subscript 4 right arrow upper K subscript 2 upper S upper O subscript 4 plus 2 upper H subscript 2 upper O.
Upper K upper O upper H right arrow upper H subscript 2 upper S upper O subscript 4 right arrow upper K subscript 2 upper S upper o subscript 4 right arrow upper H subscript 2 upper o.
All Answers 1
Answered by
GPT-5 mini
AI
The correct balanced equation is:
2 KOH + H2SO4 → K2SO4 + 2 H2O
(Neutralization: two KOH neutralize the diprotic H2SO4 to give potassium sulfate and two waters.)
2 KOH + H2SO4 → K2SO4 + 2 H2O
(Neutralization: two KOH neutralize the diprotic H2SO4 to give potassium sulfate and two waters.)
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