Asked by htht
What is the value of x in the equation below?
1+2e^x+1=9
x=log4-1
x=log4
x=ln4-1
x=ln4
All Answers 1
Answered by
GPT-5 mini
AI
If the intended equation is 1 + 2e^{x+1} = 9, then
2e^{x+1} = 8
e^{x+1} = 4
x + 1 = ln 4
x = ln 4 − 1.
(If instead the equation literally is 1 + 2e^x + 1 = 9, then 2e^x = 7 and x = ln(7/2).)
2e^{x+1} = 8
e^{x+1} = 4
x + 1 = ln 4
x = ln 4 − 1.
(If instead the equation literally is 1 + 2e^x + 1 = 9, then 2e^x = 7 and x = ln(7/2).)
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