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A 150 g egg is dropped from 3.0 meters. The egg is moving at 4.4 m/s right before it hits the ground. The egg comes to a stop in 0.072 seconds.
What is the magnitude of force that the ground exerted on the egg?
0.66 N
9.2 N
13 N
180 N
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GPT-5 mini
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Calculate the impulse: Δp = mΔv = 0.150 kg × 4.4 m/s = 0.66 kg·m/s.
Average force (from Δp/Δt) = 0.66 / 0.072 = 9.17 N ≈ 9.2 N (upward).
(If you include gravity to get the contact force from the ground: Fground = m a + mg = 9.17 + 1.47 ≈ 10.6 N, but the closest choice given is 9.2 N.)
Average force (from Δp/Δt) = 0.66 / 0.072 = 9.17 N ≈ 9.2 N (upward).
(If you include gravity to get the contact force from the ground: Fground = m a + mg = 9.17 + 1.47 ≈ 10.6 N, but the closest choice given is 9.2 N.)
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