Asked by janie
When the following solutions are mixed, which will act as a buffer? (check all that apply)
A. 50 mL of 0.05M sodium hydroxide and 50 mL of 0.1M nitrous acid
B. 50 mL of 0.1M ammonia and 50 mL of 0.1M ammonium acetate
C. 50 mL of 0.1M ammonia and 50 mL of 0.05M nitric acid
D. 50 mL of 0.1 M sodium chloride and 50 mL of 0.1M sodium acetate
E. 50 mL of 0.05M sodium hydroxide and 50 mL of 0.1M nitric acid
A. 50 mL of 0.05M sodium hydroxide and 50 mL of 0.1M nitrous acid
B. 50 mL of 0.1M ammonia and 50 mL of 0.1M ammonium acetate
C. 50 mL of 0.1M ammonia and 50 mL of 0.05M nitric acid
D. 50 mL of 0.1 M sodium chloride and 50 mL of 0.1M sodium acetate
E. 50 mL of 0.05M sodium hydroxide and 50 mL of 0.1M nitric acid
Answers
Answered by
DrBob222
A buffer is a solution of
a. a weak acid and its base (salt).
b. a weak base and its acid(salt).
Acetic acid/sodium acetate
NH3 and NH4Cl
a. a weak acid and its base (salt).
b. a weak base and its acid(salt).
Acetic acid/sodium acetate
NH3 and NH4Cl
Answered by
DrBob222
A. 50 mL of 0.05M sodium hydroxide and 50 mL of 0.1M nitrous acid
<b>For example, your first problem.
First, write the equation, then set up an ICE chart.
NaOH + HNO2 ==> NaNO2 + H2O
2.5....5.0...... 0.......0 initial
-2.5...-2.5......+2.5....+2.5 change
0......2.5.......2.5.....2.5 final
The table with the equation comes from the following data:
mmoles NaOH = 50 x 0.05 = 2.5 mmoles.
mmoles HNO2 = 50 x 0.1 = 5 mmoles.
From the final solution, you can see you have some HNO2 and its salt; that is a weak acid and its salt. Therefore, this is a buffered solution. </b>
<b>For example, your first problem.
First, write the equation, then set up an ICE chart.
NaOH + HNO2 ==> NaNO2 + H2O
2.5....5.0...... 0.......0 initial
-2.5...-2.5......+2.5....+2.5 change
0......2.5.......2.5.....2.5 final
The table with the equation comes from the following data:
mmoles NaOH = 50 x 0.05 = 2.5 mmoles.
mmoles HNO2 = 50 x 0.1 = 5 mmoles.
From the final solution, you can see you have some HNO2 and its salt; that is a weak acid and its salt. Therefore, this is a buffered solution. </b>
Answered by
bill johnson
abcd
Answered by
jake
A & D
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