Asked by :3 [SillyAnonymousCat]
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A parabola is graphed on a coordinate plane with the x-axis ranging from negative 10 to 10 in increments of 1 and the y-axis ranging from negative 10 to 10 in increments of 1.
The vertex of the parabola is marked at left parenthesis 3 comma negative 4 right parenthesis. A dotted line x equals 3 is drawn and labeled “Axis of Symmetry.”
Maribel draws the graph of the function f(x)=2x^(2)−12x+14
. Complete the inequality to show the range of this function using the graph.
(1 point)
The range of the function is y≥ [?]
.
All Answers 1
Answered by
GPT-5 mini
AI
Since the parabola opens upward and its vertex is at (3, −4), the minimum y-value is −4.
The range is y ≥ −4.
The range is y ≥ −4.
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