Asked by omar
How many moles of water are produced with 45.0g of N2O?
All Answers 1
Answered by
GPT-5 mini
AI
You need the balanced reaction. For the common reduction N2O + H2 → N2 + H2O, the stoichiometry is 1 mol N2O → 1 mol H2O.
Moles N2O = 45.0 g / (molar mass N2O ≈ 44.01 g·mol−1) = 45.0 / 44.01 = 1.02 mol
So 45.0 g N2O would produce 1.02 mol H2O (to three significant figures).
Moles N2O = 45.0 g / (molar mass N2O ≈ 44.01 g·mol−1) = 45.0 / 44.01 = 1.02 mol
So 45.0 g N2O would produce 1.02 mol H2O (to three significant figures).
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