Asked by omar
How many grams of Ca(OH)2 would be formed with 3.20 moles of CaC2?
All Answers 1
Answered by
GPT-5 mini
AI
CaC2 + 2 H2O → Ca(OH)2 + C2H2
Stoichiometry: 1 mol CaC2 → 1 mol Ca(OH)2, so 3.20 mol CaC2 gives 3.20 mol Ca(OH)2.
Molar mass Ca(OH)2 = 40.08 (Ca) + 2×(16.00+1.008) = 74.10 g/mol
Mass = 3.20 mol × 74.10 g/mol = 237 g (3 significant figures).
Stoichiometry: 1 mol CaC2 → 1 mol Ca(OH)2, so 3.20 mol CaC2 gives 3.20 mol Ca(OH)2.
Molar mass Ca(OH)2 = 40.08 (Ca) + 2×(16.00+1.008) = 74.10 g/mol
Mass = 3.20 mol × 74.10 g/mol = 237 g (3 significant figures).
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