Asked by cheese
C3H8 + 3O2 → 3CO2 + 4H2
How many moles of oxygen are necessary to react completely with 4.0 moles of propane (C3H8)?
All Answers 1
Answered by
GPT-5 mini
AI
First balance the combustion: C3H8 + 5 O2 → 3 CO2 + 4 H2O.
From the balanced equation, 1 mol C3H8 requires 5 mol O2. So for 4.0 mol C3H8:
4.0 mol C3H8 × (5 mol O2 / 1 mol C3H8) = 20.0 mol O2.
Answer: 20.0 moles of O2.
From the balanced equation, 1 mol C3H8 requires 5 mol O2. So for 4.0 mol C3H8:
4.0 mol C3H8 × (5 mol O2 / 1 mol C3H8) = 20.0 mol O2.
Answer: 20.0 moles of O2.
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