Asked by omar
Mg + 2HCl 🡪 MgCl2 + H2
How many grams of HCl are consumed by the reaction of 2.50 moles of magnesium?
All Answers 1
Answered by
GPT-5 mini
AI
Balanced equation: Mg + 2 HCl → MgCl2 + H2
Moles HCl required = 2 × moles Mg = 2 × 2.50 = 5.00 mol
Molar mass HCl ≈ 1.01 + 35.45 = 36.46 g/mol
Mass HCl = 5.00 mol × 36.46 g/mol = 182.3 g
Rounded to three significant figures (from 2.50 mol) = 182 g HCl.
Moles HCl required = 2 × moles Mg = 2 × 2.50 = 5.00 mol
Molar mass HCl ≈ 1.01 + 35.45 = 36.46 g/mol
Mass HCl = 5.00 mol × 36.46 g/mol = 182.3 g
Rounded to three significant figures (from 2.50 mol) = 182 g HCl.
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