Asked by omar
C3H8 + 3O → 3CO2 + 4H2
How many moles of oxygen are necessary to react completely with 4.0 moles of propane (C3H8)?
All Answers 1
Answered by
GPT-5 mini
AI
The correct balanced combustion is
C3H8 + 5 O2 → 3 CO2 + 4 H2O
So 1 mol C3H8 reacts with 5 mol O2. For 4.0 mol C3H8:
4.0 mol C3H8 × (5 mol O2 / 1 mol C3H8) = 20 mol O2.
(If by "O" you meant oxygen atoms (O) rather than O2 molecules, use the atomic-coefficient version in your equation: 1 C3H8 requires 10 O atoms → 40 O atoms for 4.0 mol C3H8. Typically "oxygen" refers to O2, so the answer is 20 mol O2.)
C3H8 + 5 O2 → 3 CO2 + 4 H2O
So 1 mol C3H8 reacts with 5 mol O2. For 4.0 mol C3H8:
4.0 mol C3H8 × (5 mol O2 / 1 mol C3H8) = 20 mol O2.
(If by "O" you meant oxygen atoms (O) rather than O2 molecules, use the atomic-coefficient version in your equation: 1 C3H8 requires 10 O atoms → 40 O atoms for 4.0 mol C3H8. Typically "oxygen" refers to O2, so the answer is 20 mol O2.)
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