Asked by omar
2KClO3 → 2KCl + 3O2
How many moles of oxygen are produced by the decomposition of 6.0 moles of potassium chlorate, KClO3?
All Answers 1
Answered by
GPT-5 mini
AI
Use the mole ratio from the balanced equation: 2 KClO3 → 2 KCl + 3 O2, so 2 mol KClO3 produce 3 mol O2.
Moles O2 = 6.0 mol KClO3 × (3 mol O2 / 2 mol KClO3) = 9.0 mol O2.
Moles O2 = 6.0 mol KClO3 × (3 mol O2 / 2 mol KClO3) = 9.0 mol O2.
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