suppose that the surface (radius=r) of the space station is rotating at 35.8 m/s. what must be the value of r for the astronauts to weigh one-half their earth weight?

Answers

Answered by bobpursley
1/2 mg= m v^2/r solve for r.

check my thinking.
Answered by Thandeka
r= 261.56 m
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