Asked by tt
The amount of gas (in terms of moles, mass, and molecules)
All Answers 1
Answered by
GPT-5 mini
AI
Short summary and the formulas you need
- Symbols/definitions:
- n = amount of substance (moles, mol)
- m = mass of sample (g or kg)
- M = molar mass (g·mol−1 or kg·mol−1)
- N = number of molecules (or particles)
- NA = Avogadro’s number = 6.02214076 × 10^23 mol−1
- Key relations:
- n = m / M
- N = n × NA
- m = n × M = N × (M / NA)
- mass of one molecule = M / NA (in g if M in g·mol−1; convert to kg by dividing by 1000)
- If volume/pressure/temperature are given (ideal gas):
- PV = nRT → n = PV / (RT)
- R = 0.082057 L·atm·mol−1·K−1 or 8.314462618 J·mol−1·K−1
Examples
- 2.50 mol O2 (M = 32.00 g·mol−1):
- mass m = 2.50 × 32.00 = 80.0 g
- molecules N = 2.50 × 6.022×10^23 = 1.51×10^24 molecules
- 10.0 g N2 (M = 28.02 g·mol−1):
- n = 10.0 / 28.02 = 0.357 mol
- N = 0.357 × 6.022×10^23 = 2.15×10^23 molecules
- mass of one CO2 molecule (M = 44.01 g·mol−1):
- m_one = 44.01 / 6.022×10^23 = 7.31×10^−23 g = 7.31×10^−26 kg
If you want, tell me the gas and the quantity you have (mass, moles, volume at given P & T, or number of molecules) and I’ll convert it for you.
- Symbols/definitions:
- n = amount of substance (moles, mol)
- m = mass of sample (g or kg)
- M = molar mass (g·mol−1 or kg·mol−1)
- N = number of molecules (or particles)
- NA = Avogadro’s number = 6.02214076 × 10^23 mol−1
- Key relations:
- n = m / M
- N = n × NA
- m = n × M = N × (M / NA)
- mass of one molecule = M / NA (in g if M in g·mol−1; convert to kg by dividing by 1000)
- If volume/pressure/temperature are given (ideal gas):
- PV = nRT → n = PV / (RT)
- R = 0.082057 L·atm·mol−1·K−1 or 8.314462618 J·mol−1·K−1
Examples
- 2.50 mol O2 (M = 32.00 g·mol−1):
- mass m = 2.50 × 32.00 = 80.0 g
- molecules N = 2.50 × 6.022×10^23 = 1.51×10^24 molecules
- 10.0 g N2 (M = 28.02 g·mol−1):
- n = 10.0 / 28.02 = 0.357 mol
- N = 0.357 × 6.022×10^23 = 2.15×10^23 molecules
- mass of one CO2 molecule (M = 44.01 g·mol−1):
- m_one = 44.01 / 6.022×10^23 = 7.31×10^−23 g = 7.31×10^−26 kg
If you want, tell me the gas and the quantity you have (mass, moles, volume at given P & T, or number of molecules) and I’ll convert it for you.
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.