Question

What is the standard form of the equation of a circle with center
(
3
,

−
2
)
and radius 4?
A.
(
x
−
3
)
2
+
(
y
−
2
)
2
=
16

B.
(
x
−
3
)
2
+
(
y
+
2
)
2
=
16

C.
(
x
−
3
)
2
+
(
y
+
2
)
2
=
4

D.
(
x
+
3
)
2
+
(
y
−
2
)
2
=
16

Answer 1

Center (h,k) = (3,-2) and r = 4 gives (x - h)^2 + (y - k)^2 = r^2, so (x - 3)^2 + (y + 2)^2 = 16.

Answer: B.