Question

Point upper A has coordinates left parenthesis negative 1 comma 3 right parenthesis. Point upper B has coordinates left parenthesis negative 2 comma negative 1 right parenthesis. Point upper C has coordinates left parenthesis 1 comma 0 right parenthesis. Point upper D has coordinates left parenthesis 3 comma negative 1 right parenthesis. Point upper E has coordinates left parenthesis 4 comma 3 right parenthesis. Point upper F has coordinates left parenthesis 1 comma 2 right parenthesis.Determine the congruence transformation used on △ABC
△
𝐴
𝐵
𝐶
that resulted in △DEF
△
𝐷
𝐸
𝐹
.

(1 point)
Responses

△ABC
△
𝐴
𝐵
𝐶
was reflected across the y-axis, then shifted 2 units to the right and 2 units up.
triangle upper A upper B upper C was reflected across the y -axis, then shifted 2 units to the right and 2 units up.

△ABC
△
𝐴
𝐵
𝐶
was shifted 2 units to the right and 2 units up, then rotated 180°
180
°
(counterclockwise).
triangle upper A upper B upper C was shifted 2 units to the right and 2 units up, then rotated 180 degrees (counterclockwise).

△ABC
△
𝐴
𝐵
𝐶
was shifted 2 units to the left and 2 units up, then reflected across the y-axis.
triangle upper A upper B upper C was shifted 2 units to the left and 2 units up, then reflected across the y -axis.

△ABC
△
𝐴
𝐵
𝐶
was rotated −180°
−
180
°
(clockwise) or 180°
180
°
(counterclockwise), then shifted 2 units to the right and 2 up

Answer 1

Answer: △ABC was rotated 180° about the origin, then translated 2 units right and 2 units up.

Check:
- A(-1,3) → rotate 180° → (1,-3) → + (2,2) → (3,-1) = D
- B(-2,-1) → rotate 180° → (2,1) → + (2,2) → (4,3) = E
- C(1,0) → rotate 180° → (-1,0) → + (2,2) → (1,2) = F