Question

Use the image to answer the question.

A coordinate plane shows an upward-opening parabola with a plotted point. Both axes range from negative 20 to 20 in increments of 5.
The parabola passes through left parenthesis 2 comma 20 right parenthesis and left parenthesis 3 comma 15 right parenthesis, then continues to its vertex at the plotted and labeled point left parenthesis 4 comma 8 right parenthesis. It continues through left parenthesis 5 comma 10 right parenthesis and left parenthesis 7 comma 20 right parenthesis. All values are approximate.


What is the vertex form of the graphed equation?

(1 point)
Responses

y=−2(x−4)^(2)+8

y equals negative 2 left parenthesis x minus 4 right parenthesis squared plus 8

y=2(x−4)^(2)−8

y equals 2 left parenthesis x minus 4 right parenthesis squared minus 8

y=2(x−4)^(2)+8

y equals 2 left parenthesis x minus 4 right parenthesis squared plus 8

y=2(x+4)^(2)+8

y equals 2 left parenthesis x plus 4 right parenthesis squared plus 8

Answer 1

Vertex form is y = a(x − 4)^2 + 8. Use point (5,10): 10 = a(1)^2 + 8 ⇒ a = 2. So y = 2(x − 4)^2 + 8.