Question

Which quadratic function has a range that can be described as y≤10.5
?(1 point)
Responses

f(x)=6(x+4)^(2)+10.5

f left parenthesis x right parenthesis equals 6 left parenthesis x plus 4 right parenthesis squared plus 10.5

f(x)=10.5(x−4)^(2)−6

f left parenthesis x right parenthesis equals 10.5 left parenthesis x minus 4 right parenthesis squared minus 6

f(x)=−6(x−10.5)^(2)+4

f left parenthesis x right parenthesis equals negative 6 left parenthesis x minus 10.5 right parenthesis squared plus 4

f(x)=−6(x+4)^(2)+10.5

f left parenthesis x right parenthesis equals negative 6 left parenthesis x plus 4 right parenthesis squared plus 10.5

Answer 1

f(x) = −6(x+4)^2 + 10.5

Reason: with a < 0 the parabola opens downward and its maximum is the vertex value k = 10.5, so the range is y ≤ 10.5.